What is the indefinite integral of Sinx?
What is the indefinite integral of Sinx?
What is the indefinite integral of Sinx?
∫sin(x)dx=-cos(x)+C, ∫cos(x)dx=sin(x)+C, and ∫eˣdx=eˣ+C.
What is the formula of Sinx COSX?
Answer : The expression for sin x + cos x in terms of sine is sin x + sin (π / 2 – x). Let us see the detailed solution now.
What is the max value of Sinx COSX?
Sinx + cosx is positive as we want max value. = -2/√2 = -√2 [this satisfies the condition of the maximum graph (y) at 1st derivative, which is positive (+) before the turning point, and at 2nd derivative, which is negative after the turning point]. its sqrt2. U can divide and multiply sinx + cosx by sqrt2.
What is integration of COSX?
The integral of cos x dx is sin x. Mathematically, this is written as ∫ cos x dx = sin x + C, where, C is the integration constant.
What is antiderivative COSX?
Thus we sometimes say that the antiderivative of a function is a function plus an arbitrary constant. Thus the antiderivative of cos x \cos x cosx is ( sin x ) + c (\sin x) + c (sinx)+c. The more common name for the antiderivative is the indefinite integral.
What is formula of Sinx?
Using one of the trigonometric formulas, we can write sin x as, sin x = cos (π/2 – x).
What is the equation for Sinx?
Solutions for Trigonometric Equations
Equations | Solutions |
---|---|
sin x = sin θ | x = nπ + (-1)nθ, where θ ∈ [-π/2, π/2] |
cos x = cos θ | x = 2nπ ± θ, where θ ∈ (0, π] |
tan x = tan θ | x = nπ + θ, where θ ∈ (-π/2 , π/2] |
sin 2x = sin 2θ | x = nπ ± θ |
What is the second derivative of sinx?
Explanation: ddxsinx=cosx .
What is the derivative of sinx?
cos x
The derivative of sin x is denoted by d/dx (sin x) = cos x. The other way to represent the sine function is (sin x)’ = cos x.
What is the maximum value of Sinx COSX root2?
Therefore, maximum value of 2 .